因式分解 p^2-6p+9

解答

因式分解

p^{2} - 6 p + 9

(p - 3)^{2}

求解步骤

p^{2} - 6 p + 9

改写为形式

a^{2} + 2 ab + b^{2} :

9 = 3^{2}

- 6 p = - 2 p \cdot 3

= p^{2} - 2 p \cdot 3 + 3^{2}

使用完全平方公式:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

p^{2} - 2 p \cdot 3 + 3^{2} = (p - 3)^{2}

= (p - 3)^{2}

12 x^{2} - 16 = 0

7 (t + 8) = 8 t

- \frac{1}{2} \leq \frac{4 - 3 x}{5} \leq \frac{1}{4}

2 x^{2} - 7 x - 1 = 0

4 k - 7 (5 k - 2) \geq 169