y^2-11y+28=0

解

y^{2} - 11 y + 28 = 0

y = 7, y = 4

解答ステップ

y^{2} - 11 y + 28 = 0

解くとthe二次式

y_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 28}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 28 = 3

y_{1, 2} = \frac{- ( - 11 ) \pm 3}{2 \cdot 1}

解を分離する

y_{1} = \frac{- ( - 11 ) + 3}{2 \cdot 1}, y_{2} = \frac{- ( - 11 ) - 3}{2 \cdot 1}

y = \frac{- ( - 11 ) + 3}{2 \cdot 1} : 7

y = \frac{- ( - 11 ) - 3}{2 \cdot 1} : 4

二次equationの解:

y = 7, y = 4