faktorisieren 8c^6+19c^3-27

Lösung

faktorisieren

8 c^{6} + 19 c^{3} - 27

(c - 1) (c^{2} + c + 1) (2 c + 3) (4 c^{2} - 6 c + 9)

Schritte zur Lösung

8 c^{6} + 19 c^{3} - 27

Wende den rationalen Nullstellentest an

= (c - 1) \frac{8 c ^{6} + 19 c ^{3} - 27}{c - 1}

\frac{8 c ^{6} + 19 c ^{3} - 27}{c - 1} = 8 c^{5} + 8 c^{4} + 8 c^{3} + 27 c^{2} + 27 c + 27

= (c - 1) (8 c^{5} + 8 c^{4} + 8 c^{3} + 27 c^{2} + 27 c + 27)

Faktorisiere

8 c^{5} + 8 c^{4} + 8 c^{3} + 27 c^{2} + 27 c + 27 : (c^{2} + c + 1) (2 c + 3) (2^{2} c^{2} - 3 \cdot 2 c + 3^{2})

= (c - 1) (c^{2} + c + 1) (2 c + 3) (2^{2} c^{2} - 3 \cdot 2 c + 3^{2})

Vereinfache

(c - 1) (c^{2} + c + 1) (2 c + 3) (2^{2} c^{2} - 3 \cdot 2 c + 3^{2}) : (c - 1) (c^{2} + c + 1) (2 c + 3) (4 c^{2} - 6 c + 9)

= (c - 1) (c^{2} + c + 1) (2 c + 3) (4 c^{2} - 6 c + 9)

s im pl i f y 9 x^{2} \cdot 9 y^{5}

s im pl i f y 3 x^{- \frac{1}{2}}

- 2 (u + 3) = 3 (u + 4) + 7

f a c t or 2 + 2 i

2 (a + 2) = 3 (a - 1)