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Beliebt Algebra >

faktorisieren 2x^4+5x^3-11x^2-20x+12

Lösung

faktorisieren

2 x^{4} + 5 x^{3} - 11 x^{2} - 20 x + 12

Lösung

(2 x - 1) (x + 3) (x + 2) (x - 2)

Schritte zur Lösung

2 x^{4} + 5 x^{3} - 11 x^{2} - 20 x + 12

Wende den rationalen Nullstellentest an

= (2 x - 1) \frac{2 x ^{4} + 5 x ^{3} - 11 x ^{2} - 20 x + 12}{2 x - 1}

\frac{2 x ^{4} + 5 x ^{3} - 11 x ^{2} - 20 x + 12}{2 x - 1} = x^{3} + 3 x^{2} - 4 x - 12

= (2 x - 1) (x^{3} + 3 x^{2} - 4 x - 12)

Faktorisiere

x^{3} + 3 x^{2} - 4 x - 12 : (x + 3) (x + 2) (x - 2)

= (2 x - 1) (x + 3) (x + 2) (x - 2)

Beliebte Beispiele

4 x = x - 15

(x-4)^2=(x-2)^2

(x - 4)^{2} = (x - 2)^{2}

f = 6^{1}

- 36 = \frac{x}{2}

faktorisieren 4b^2+28b+4

f a c t or 4 b^{2} + 28 b + 4