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受欢迎的代数 >

t=-4.9t^2+16.3t+15

解答

t = - 4.9 t^{2} + 16.3 t + 15

解答

t = - \frac{- 153 + 52809}{98}, t = \frac{153 + 52809}{98}

+1

十进制

t = - 0.78369 \dots, t = 3.90614 \dots

求解步骤

t = - 4.9 t^{2} + 16.3 t + 15

在两边乘以

10

t \cdot 10 = - 49 t^{2} + 163 t + 150

交换两边

- 49 t^{2} + 163 t + 150 = t \cdot 10

将

t 10

para o lado esquerdo

- 49 t^{2} + 153 t + 150 = 0

使用求根公式求解

t_{1, 2} = \frac{- 153 \pm 15 3 ^{2} - 4 ( - 49 ) \cdot 150}{2 ( - 49 )}

15 3^{2} - 4 (- 49) \cdot 150 = 52809

t_{1, 2} = \frac{- 153 \pm 52809}{2 ( - 49 )}

将解分隔开

t_{1} = \frac{- 153 + 52809}{2 ( - 49 )}, t_{2} = \frac{- 153 - 52809}{2 ( - 49 )}

t = \frac{- 153 + 52809}{2 ( - 49 )} : - \frac{- 153 + 52809}{98}

t = \frac{- 153 - 52809}{2 ( - 49 )} : \frac{153 + 52809}{98}

二次方程组的解是:

t = - \frac{- 153 + 52809}{98}, t = \frac{153 + 52809}{98}

作图

流行的例子

n - 2 > - 22

\frac{1}{4} x + 6 = 42

化简 3/4+2/5-3/20

s im pl i f y \frac{3}{4} + \frac{2}{5} - \frac{3}{20}

s im pl i f y - 4 \cdot 5

因式分解 4p+12

f a c t or 4 p + 12