化简 (x-i)^2

解答

化简

(x - i)^{2}

(x^{2} - 1) - 2 x i

求解步骤

(x - i)^{2}

使用完全平方公式:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(x - i)^{2} = x^{2} - 2 x i + i^{2}

= x^{2} - 2 x i + i^{2}

使用虚数运算法则:

i^{2} = - 1

= x^{2} - 2 x i - 1

Rewrite in standard complex form:

(x^{2} - 1) - 2 x i

= (x^{2} - 1) - 2 x i

e x p an d \frac{( d ^{6} - c ^{6} ) b + 1 aπ}{6 b ^{2}}

e x p an d (cos^{2} (t) - cos (t) sin (t)) \cdot (- sin (t) + cos (t))

e x p an d \frac{d}{d x} ((1 + x^{2}) arctan (x)) - x

e x p an d 6 y^{2} d x - x (2 x^{3} + y) d y

s im pl i f y (6 + x)^{2}