展开 3.5((18.6-4.8x)/(3.5^2))^2

解答

展开

3.5 (\frac{18.6 - 4.8 x}{3. 5 ^{2}})^{2}

\frac{23.04 x ^{2}}{42.875} - \frac{178.56 x}{42.875} + \frac{345.96}{42.875}

求解步骤

3.5 (\frac{18.6 - 4.8 x}{3. 5 ^{2}})^{2}

(\frac{18.6 - 4.8 x}{3. 5 ^{2}})^{2} = \frac{345.96 - 178.56 x + 23.04 x ^{2}}{3. 5 ^{4}}

= 3.5 \cdot \frac{23.04 x ^{2} - 178.56 x + 345.96}{3. 5 ^{4}}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 345.96 - 178.56 x + 23.04 x ^{2} ) \cdot 3.5}{3. 5 ^{4}}

约分:

3.5

= \frac{345.96 - 178.56 x + 23.04 x ^{2}}{3. 5 ^{3}}

3. 5^{3} = 42.875

= \frac{345.96 - 178.56 x + 23.04 x ^{2}}{42.875}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{345.96 - 178.56 x + 23.04 x ^{2}}{42.875} = \frac{345.96}{42.875} - \frac{178.56 x}{42.875} + \frac{23.04 x ^{2}}{42.875}

= \frac{345.96}{42.875} - \frac{178.56 x}{42.875} + \frac{23.04 x ^{2}}{42.875}

改写为标准形式

= \frac{23.04 x ^{2}}{42.875} - \frac{178.56 x}{42.875} + \frac{345.96}{42.875}

e x p an d 1 (\frac{3}{2 x})^{0} (\frac{1}{y})^{6}

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