展开 (2x^4-1)'(5x^3-6)+(5x^3-6)'(2x^4-1)

解答

展开

(2 x^{4} - 1)^{'} \cdot (5 x^{3} - 6) + (5 x^{3} - 6)^{'} \cdot (2 x^{4} - 1)

5 x^{3} (2 x^{4} - 1)' - 6 (2 x^{4} - 1)' + 2 x^{4} (5 x^{3} - 6)' - (5 x^{3} - 6)'

求解步骤

(2 x^{4} - 1)^{'} (5 x^{3} - 6) + (5 x^{3} - 6)^{'} (2 x^{4} - 1)

乘开

(2 x^{4} - 1)^{'} (5 x^{3} - 6) : 5 x^{3} (2 x^{4} - 1)^{'} - 6 (2 x^{4} - 1)^{'}

= 5 x^{3} (2 x^{4} - 1)^{'} - 6 (2 x^{4} - 1)^{'} + (5 x^{3} - 6)^{'} (2 x^{4} - 1)

乘开

(5 x^{3} - 6)^{'} (2 x^{4} - 1) : 2 x^{4} (5 x^{3} - 6)^{'} - (5 x^{3} - 6)^{'}

= 5 x^{3} (2 x^{4} - 1)^{'} - 6 (2 x^{4} - 1)^{'} + 2 x^{4} (5 x^{3} - 6)^{'} - (5 x^{3} - 6)^{'}

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