解答
展开 log535(x+9)9
解答
31log5(x9+81x8+2916x7+61236x6+826686x5+7440174x4+44641044x3+172186884x2+387420489x+387420489)−31
求解步骤
log535(x+9)9
35(x+9)9=35x9+81x8+2916x7+61236x6+826686x5+7440174x4+44641044x3+172186884x2+387420489x+387420489
=log5(35x9+81x8+2916x7+61236x6+826686x5+7440174x4+44641044x3+172186884x2+387420489x+387420489)
改写为=log5((5x9+81x8+2916x7+61236x6+826686x5+7440174x4+44641044x3+172186884x2+387420489x+387420489)31)
使用对数运算法则: loga(xb)=b⋅loga(x), 假定 x≥0=31log5(5x9+81x8+2916x7+61236x6+826686x5+7440174x4+44641044x3+172186884x2+387420489x+387420489)
化简 log5(5x9+81x8+2916x7+61236x6+826686x5+7440174x4+44641044x3+172186884x2+387420489x+387420489):log5(x9+81x8+2916x7+61236x6+826686x5+7440174x4+44641044x3+172186884x2+387420489x+387420489)−1
=31(log5(x9+81x8+2916x7+61236x6+826686x5+7440174x4+44641044x3+172186884x2+387420489x+387420489)−1)
使用分配律: a(b−c)=ab−aca=31,b=log5(x9+81x8+2916x7+61236x6+826686x5+7440174x4+44641044x3+172186884x2+387420489x+387420489),c=1=31log5(x9+81x8+2916x7+61236x6+826686x5+7440174x4+44641044x3+172186884x2+387420489x+387420489)−31⋅1
=31log5(x9+81x8+2916x7+61236x6+826686x5+7440174x4+44641044x3+172186884x2+387420489x+387420489)−1⋅31
乘以:1⋅31=31=31log5(x9+81x8+2916x7+61236x6+826686x5+7440174x4+44641044x3+172186884x2+387420489x+387420489)−31