化简 2(sqrt(7)-2)

解答

化简

2 (7 - 2)

27 - 4

十进制

1.29150 \dots

求解步骤

2 (7 - 2)

使用分配律:

a (b - c) = ab - a c

2 (7 - 2) = 27 - 2 \cdot 2

= 27 - 2 \cdot 2

数字相乘:

2 \cdot 2 = 4

= 27 - 4

e x p an d A (3, - 4) y B (5, 1)

e x p an d ((6) (2 a e^{a x} + a^{2} e^{a x} x)) (x e^{a x})

e x p an d 1 + 2 t^{2} + 9 t 4

\frac{d}{d P} ((V^{1}) (q^{4} + P))

e x p an d (y \cdot e^{x} + x \cdot y \cdot e^{x} + 1) d x + (x \cdot e^{x}) d y