8x^2+16x=0

解

8 x^{2} + 16 x = 0

x = 0, x = - 2

解答ステップ

8 x^{2} + 16 x = 0

解くとthe二次式

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

1 6^{2} - 4 \cdot 8 \cdot 0 = 16

x_{1, 2} = \frac{- 16 \pm 16}{2 \cdot 8}

解を分離する

x_{1} = \frac{- 16 + 16}{2 \cdot 8}, x_{2} = \frac{- 16 - 16}{2 \cdot 8}

x = \frac{- 16 + 16}{2 \cdot 8} : 0

x = \frac{- 16 - 16}{2 \cdot 8} : - 2

二次equationの解:

x = 0, x = - 2