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受欢迎的代数 >

G(x)=-3x^2+9x+5

解答

G (x) = - 3 x^{2} + 9 x + 5

解答

x = - \frac{- 9 + G + G ^{2} - 18 G + 141}{6}, x = - \frac{- 9 + G - G ^{2} - 18 G + 141}{6}

求解步骤

G (x) = - 3 x^{2} + 9 x + 5

整理后得

G x = - 3 x^{2} + 9 x + 5

交换两边

- 3 x^{2} + 9 x + 5 = G x

将

G x

para o lado esquerdo

- 3 x^{2} + 9 x + 5 - G x = 0

改写成标准形式

a x^{2} + b x + c = 0

- 3 x^{2} + (9 - G) x + 5 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( 9 - G ) \pm ( 9 - G ) ^{2} - 4 ( - 3 ) \cdot 5}{2 ( - 3 )}

化简

(9 - G)^{2} - 4 (- 3) \cdot 5 : G^{2} - 18 G + 141

x_{1, 2} = \frac{- ( 9 - G ) \pm G ^{2} - 18 G + 141}{2 ( - 3 )}

将解分隔开

x_{1} = \frac{- ( 9 - G ) + G ^{2} - 18 G + 141}{2 ( - 3 )}, x_{2} = \frac{- ( 9 - G ) - G ^{2} - 18 G + 141}{2 ( - 3 )}

x = \frac{- ( 9 - G ) + G ^{2} - 18 G + 141}{2 ( - 3 )} : - \frac{- 9 + G + G ^{2} - 18 G + 141}{6}

x = \frac{- ( 9 - G ) - G ^{2} - 18 G + 141}{2 ( - 3 )} : - \frac{- 9 + G - G ^{2} - 18 G + 141}{6}

二次方程组的解是:

x = - \frac{- 9 + G + G ^{2} - 18 G + 141}{6}, x = - \frac{- 9 + G - G ^{2} - 18 G + 141}{6}

作图

流行的例子

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