6t^2-30t+24=0

解

6 t^{2} - 30 t + 24 = 0

t = 4, t = 1

解答ステップ

6 t^{2} - 30 t + 24 = 0

解くとthe二次式

t_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 6 \cdot 24}{2 \cdot 6}

(- 30)^{2} - 4 \cdot 6 \cdot 24 = 18

t_{1, 2} = \frac{- ( - 30 ) \pm 18}{2 \cdot 6}

解を分離する

t_{1} = \frac{- ( - 30 ) + 18}{2 \cdot 6}, t_{2} = \frac{- ( - 30 ) - 18}{2 \cdot 6}

t = \frac{- ( - 30 ) + 18}{2 \cdot 6} : 4

t = \frac{- ( - 30 ) - 18}{2 \cdot 6} : 1

二次equationの解:

t = 4, t = 1