x^2-15x+54=0

解

x^{2} - 15 x + 54 = 0

x = 9, x = 6

解答ステップ

x^{2} - 15 x + 54 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 54}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 54 = 3

x_{1, 2} = \frac{- ( - 15 ) \pm 3}{2 \cdot 1}

解を分離する

x_{1} = \frac{- ( - 15 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 3}{2 \cdot 1}

x = \frac{- ( - 15 ) + 3}{2 \cdot 1} : 9

x = \frac{- ( - 15 ) - 3}{2 \cdot 1} : 6

二次equationの解:

x = 9, x = 6