p^2+8p=0

解

p^{2} + 8 p = 0

p = 0, p = - 8

解答ステップ

p^{2} + 8 p = 0

解くとthe二次式

p_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 0 = 8

p_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 1}

解を分離する

p_{1} = \frac{- 8 + 8}{2 \cdot 1}, p_{2} = \frac{- 8 - 8}{2 \cdot 1}

p = \frac{- 8 + 8}{2 \cdot 1} : 0

p = \frac{- 8 - 8}{2 \cdot 1} : - 8

二次equationの解:

p = 0, p = - 8