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受欢迎的代数 >

r^2+r+6=0

解答

r^{2} + r + 6 = 0

解答

r = - \frac{1}{2} + i \frac{23}{2}, r = - \frac{1}{2} - i \frac{23}{2}

求解步骤

r^{2} + r + 6 = 0

使用求根公式求解

r_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

化简

1^{2} - 4 \cdot 1 \cdot 6 : 23 i

r_{1, 2} = \frac{- 1 \pm 23 i}{2 \cdot 1}

将解分隔开

r_{1} = \frac{- 1 + 23 i}{2 \cdot 1}, r_{2} = \frac{- 1 - 23 i}{2 \cdot 1}

r = \frac{- 1 + 23 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{23}{2}

r = \frac{- 1 - 23 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{23}{2}

二次方程组的解是:

r = - \frac{1}{2} + i \frac{23}{2}, r = - \frac{1}{2} - i \frac{23}{2}

作图

流行的例子

solvefor y,(x-3)^2+(y+2)^2=4

so l v e f or y, (x - 3)^{2} + (y + 2)^{2} = 4

(2 s - 1)^{2} = 225

a (b^{2} - 4) = n

5 (2 x + 1)^{2} = 20

r^{2} + 144 = 0