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受欢迎的代数 >

(k-1)p^2+4p+7=0

解答

(k - 1) p^{2} + 4 p + 7 = 0

解答

p = \frac{- 2 + - 7 k + 11}{k - 1}, p = - \frac{- 7 k + 11 + 2}{k - 1}; k \neq = 1

求解步骤

(k - 1) p^{2} + 4 p + 7 = 0

使用求根公式求解

p_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( k - 1 ) \cdot 7}{2 ( k - 1 )}

化简

4^{2} - 4 (k - 1) \cdot 7 : 2 - 7 k + 11

p_{1, 2} = \frac{- 4 \pm 2 - 7 k + 11}{2 ( k - 1 )}; k \neq = 1

将解分隔开

p_{1} = \frac{- 4 + 2 - 7 k + 11}{2 ( k - 1 )}, p_{2} = \frac{- 4 - 2 - 7 k + 11}{2 ( k - 1 )}

p = \frac{- 4 + 2 - 7 k + 11}{2 ( k - 1 )} : \frac{- 2 + - 7 k + 11}{k - 1}

p = \frac{- 4 - 2 - 7 k + 11}{2 ( k - 1 )} : - \frac{- 7 k + 11 + 2}{k - 1}

二次方程组的解是:

p = \frac{- 2 + - 7 k + 11}{k - 1}, p = - \frac{- 7 k + 11 + 2}{k - 1}; k \neq = 1

作图

流行的例子

y^{2} = 18

y^{2} = 15

y^{2} = 7 y

- 3 x - 12 = x - 3 x^{2}

(x-1)^3-(x-2)^3=27

(x - 1)^{3} - (x - 2)^{3} = 27