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受欢迎的代数 >

c(x)=x^2+6x+128

解答

c (x) = x^{2} + 6 x + 128

解答

x = \frac{- 6 + c + c ^{2} - 12 c - 476}{2}, x = \frac{- 6 + c - c ^{2} - 12 c - 476}{2}

求解步骤

c (x) = x^{2} + 6 x + 128

整理后得

c x = x^{2} + 6 x + 128

交换两边

x^{2} + 6 x + 128 = c x

将

c x

para o lado esquerdo

x^{2} + 6 x + 128 - c x = 0

改写成标准形式

a x^{2} + b x + c = 0

x^{2} + (6 - c) x + 128 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( 6 - c ) \pm ( 6 - c ) ^{2} - 4 \cdot 1 \cdot 128}{2 \cdot 1}

化简

(6 - c)^{2} - 4 \cdot 1 \cdot 128 : c^{2} - 12 c - 476

x_{1, 2} = \frac{- ( 6 - c ) \pm c ^{2} - 12 c - 476}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( 6 - c ) + c ^{2} - 12 c - 476}{2 \cdot 1}, x_{2} = \frac{- ( 6 - c ) - c ^{2} - 12 c - 476}{2 \cdot 1}

x = \frac{- ( 6 - c ) + c ^{2} - 12 c - 476}{2 \cdot 1} : \frac{- 6 + c + c ^{2} - 12 c - 476}{2}

x = \frac{- ( 6 - c ) - c ^{2} - 12 c - 476}{2 \cdot 1} : \frac{- 6 + c - c ^{2} - 12 c - 476}{2}

二次方程组的解是:

x = \frac{- 6 + c + c ^{2} - 12 c - 476}{2}, x = \frac{- 6 + c - c ^{2} - 12 c - 476}{2}

作图

流行的例子

6 u^{2} - u - 2 = 0

(4 x - 3) (3 x + 4) = 0

5(2x^2-3)=4(x^2-10)

5 (2 x^{2} - 3) = 4 (x^{2} - 10)

因式分解 x^2-x-42=0

f a c t or x^{2} - x - 42 = 0

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