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受欢迎的代数 >

solvefor a,(a+b)^3=a^3+b^3

解答

求解

a, (a + b)^{3} = a^{3} + b^{3}

解答

a = 0, a = - b; b \neq = 0

求解步骤

(a + b)^{3} = a^{3} + b^{3}

展开

(a + b)^{3} : a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}

a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3} = a^{3} + b^{3}

将

b^{3}

para o lado esquerdo

a^{3} + 3 a^{2} b + 3 a b^{2} = a^{3}

将

a^{3}

para o lado esquerdo

3 a^{2} b + 3 a b^{2} = 0

改写成标准形式

a x^{2} + b x + c = 0

3 b a^{2} + 3 b^{2} a = 0

使用求根公式求解

a_{1, 2} = \frac{- 3 b ^{2} \pm ( 3 b ^{2} ) ^{2} - 4 \cdot 3 b \cdot 0}{2 \cdot 3 b}

化简

(3 b^{2})^{2} - 4 \cdot 3 b \cdot 0 : 3 b^{2}

a_{1, 2} = \frac{- 3 b ^{2} \pm 3 b ^{2}}{2 \cdot 3 b}; b \neq = 0

将解分隔开

a_{1} = \frac{- 3 b ^{2} + 3 b ^{2}}{2 \cdot 3 b}, a_{2} = \frac{- 3 b ^{2} - 3 b ^{2}}{2 \cdot 3 b}

a = \frac{- 3 b ^{2} + 3 b ^{2}}{2 \cdot 3 b} : 0

a = \frac{- 3 b ^{2} - 3 b ^{2}}{2 \cdot 3 b} : - b

二次方程组的解是:

a = 0, a = - b; b \neq = 0

作图

流行的例子

solvefor x,(x-5)^2-(y+3)^2=0

so l v e f or x, (x - 5)^{2} - (y + 3)^{2} = 0

3x^2-5x-10=x^2+3x+14

3 x^{2} - 5 x - 10 = x^{2} + 3 x + 14

x^{2} - 8 x = - 14

x^{2} - 8 x = - 27

3 x^{2} + 2 = 29