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受欢迎的代数 >

-16t^2+288t+216=0

解答

- 16 t^{2} + 288 t + 216 = 0

解答

t = - \frac{3 ( 42 - 6 )}{2}, t = \frac{3 ( 6 + 42 )}{2}

+1

十进制

t = - 0.72111 \dots, t = 18.72111 \dots

求解步骤

- 16 t^{2} + 288 t + 216 = 0

使用求根公式求解

t_{1, 2} = \frac{- 288 \pm 28 8 ^{2} - 4 ( - 16 ) \cdot 216}{2 ( - 16 )}

28 8^{2} - 4 (- 16) \cdot 216 = 4842

t_{1, 2} = \frac{- 288 \pm 48 42}{2 ( - 16 )}

将解分隔开

t_{1} = \frac{- 288 + 48 42}{2 ( - 16 )}, t_{2} = \frac{- 288 - 48 42}{2 ( - 16 )}

t = \frac{- 288 + 48 42}{2 ( - 16 )} : - \frac{3 ( 42 - 6 )}{2}

t = \frac{- 288 - 48 42}{2 ( - 16 )} : \frac{3 ( 6 + 42 )}{2}

二次方程组的解是:

t = - \frac{3 ( 42 - 6 )}{2}, t = \frac{3 ( 6 + 42 )}{2}

作图

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