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受欢迎的代数 >

(10-x)(-12-x)+40=0

解答

(10 - x) (- 12 - x) + 40 = 0

解答

x = 8, x = - 10

求解步骤

(10 - x) (- 12 - x) + 40 = 0

展开

(10 - x) (- 12 - x) + 40 : x^{2} + 2 x - 80

x^{2} + 2 x - 80 = 0

使用求根公式求解

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 80 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 80) = 18

x_{1, 2} = \frac{- 2 \pm 18}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- 2 + 18}{2 \cdot 1}, x_{2} = \frac{- 2 - 18}{2 \cdot 1}

x = \frac{- 2 + 18}{2 \cdot 1} : 8

x = \frac{- 2 - 18}{2 \cdot 1} : - 10

二次方程组的解是:

x = 8, x = - 10

作图

流行的例子

x(4x-1)=3x(x-2)+6

x (4 x - 1) = 3 x (x - 2) + 6

solvefor x,x^2-kx+16=0

so l v e f or x, x^{2} - k x + 16 = 0

x^{2} = - 1 - 4 x

2 x^{2} - 10 x = - 7 x - 2

b^{2} = 81