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受欢迎的代数 >

x(4x-3)/5-(2x-3)/2 =-2

解答

x \frac{4 x - 3}{5} - \frac{2 x - 3}{2} = - 2

解答

x = 1 + i \frac{3 6}{4}, x = 1 - i \frac{3 6}{4}

求解步骤

x \frac{4 x - 3}{5} - \frac{2 x - 3}{2} = - 2

在两边乘以

2

\frac{2 x ( 4 x - 3 )}{5} - (2 x - 3) = - 4

展开

\frac{2 x ( 4 x - 3 )}{5} - (2 x - 3) : \frac{8 x ^{2}}{5} - \frac{16 x}{5} + 3

\frac{8 x ^{2}}{5} - \frac{16 x}{5} + 3 = - 4

将

4

para o lado esquerdo

\frac{8 x ^{2} - 16 x}{5} + 7 = 0

改写成标准形式

a x^{2} + b x + c = 0

\frac{8 x ^{2}}{5} - \frac{16 x}{5} + 7 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - \frac{16}{5} ) \pm ( - \frac{16}{5} ) ^{2} - 4 \cdot \frac{8}{5} \cdot 7}{2 \cdot \frac{8}{5}}

化简

(- \frac{16}{5})^{2} - 4 \cdot \frac{8}{5} \cdot 7 : i \frac{12 6}{5}

x_{1, 2} = \frac{- ( - \frac{16}{5} ) \pm i \frac{12 6}{5}}{2 \cdot \frac{8}{5}}

将解分隔开

x_{1} = \frac{- ( - \frac{16}{5} ) + i \frac{12 6}{5}}{2 \cdot \frac{8}{5}}, x_{2} = \frac{- ( - \frac{16}{5} ) - i \frac{12 6}{5}}{2 \cdot \frac{8}{5}}

x = \frac{- ( - \frac{16}{5} ) + i \frac{12 6}{5}}{2 \frac{8}{5}} : 1 + i \frac{3 6}{4}

x = \frac{- ( - \frac{16}{5} ) - i \frac{12 6}{5}}{2 \frac{8}{5}} : 1 - i \frac{3 6}{4}

二次方程组的解是:

x = 1 + i \frac{3 6}{4}, x = 1 - i \frac{3 6}{4}

作图

流行的例子

9 x (x + 1) 2 - 4 = 0

p^{2} - 2 p - 48 = 0

x^{2} - 5 x - 1 = - 5

solvefor r,A=pirh+pir^2

so l v e f or r, A = π r h + π r^{2}

- 3 x^{2} + 144 x = 0