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受欢迎的代数 >

-3λ+λ^2+2=0

解答

- 3 λ + λ^{2} + 2 = 0

解答

λ = 2, λ = 1

求解步骤

- 3 λ + λ^{2} + 2 = 0

改写成标准形式

a x^{2} + b x + c = 0

λ^{2} - 3 λ + 2 = 0

使用求根公式求解

λ_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 2 = 1

λ_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 1}

将解分隔开

λ_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 1}, λ_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 1}

λ = \frac{- ( - 3 ) + 1}{2 \cdot 1} : 2

λ = \frac{- ( - 3 ) - 1}{2 \cdot 1} : 1

二次方程组的解是:

λ = 2, λ = 1

作图

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