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受欢迎的代数 >

b^2+6b=41

解答

b^{2} + 6 b = 41

解答

b = - 3 + 52, b = - 3 - 52

+1

十进制

b = 4.07106 \dots, b = - 10.07106 \dots

求解步骤

b^{2} + 6 b = 41

将

41

para o lado esquerdo

b^{2} + 6 b - 41 = 0

使用求根公式求解

b_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 41 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 41) = 102

b_{1, 2} = \frac{- 6 \pm 10 2}{2 \cdot 1}

将解分隔开

b_{1} = \frac{- 6 + 10 2}{2 \cdot 1}, b_{2} = \frac{- 6 - 10 2}{2 \cdot 1}

b = \frac{- 6 + 10 2}{2 \cdot 1} : - 3 + 52

b = \frac{- 6 - 10 2}{2 \cdot 1} : - 3 - 52

二次方程组的解是:

b = - 3 + 52, b = - 3 - 52

作图

流行的例子

- 5 x^{2} + 3 x + 10 = 0

1500x^2+200x+18=0

1500 x^{2} + 200 x + 18 = 0

solvefor x,yx^2-1+6y=5xy+x

so l v e f or x, y x^{2} - 1 + 6 y = 5 x y + x

x^{2} + 3 x - 27 = 0

solvefor a,m(a)=-0.2a^2+7a+68

so l v e f or a, m (a) = - 0.2 a^{2} + 7 a + 68