erweitern 6(3x-10=5(2x+15))

Lösung

erweitern

6 (3 x - 10 = 5 (2 x + 15))

18 x - 60 = 10 x + 75

Schritte zur Lösung

6 (3 x - 10 = 5 (2 x + 15))

= 6 (3 x - 10 \cdot 5 = (2 x + 15))

Wende das Distributivgesetz an:

a (b - c) = ab - a c

a = 6, b = 3 x, c = 10 = 5 (2 x + 15)

6 \cdot 3 x - 6 \cdot 10 = 5 (2 x + 15)

Vereinfache

6 \cdot 3 x - 6 \cdot 10 = 5 (2 x + 15) : 18 x - 60 = 10 x + 75

18 x - 60 = 10 x + 75

e x p an d \frac{( x + 2 ) ( x + 1 ) ( 2 x + 3 )}{( x + 2 ) ( x + 1 )}

e x p an d \frac{( n + 1 ) ( n + 2 ) ( 2 n + 9 )}{6}

e x p an d \frac{2}{x ( x ^{2} - 16 )}

f (x) = \frac{2 x ^{5} + 28 x ^{3} - 6 x}{( x ^{2} - 1 ) ^{4}}

e x p an d \frac{100 a ^{2} - 20 a + 1}{100}