展開する p_{1}(p^1=3.25+1/4 p_{1})

解

展開する

p_{1} (p^{1} = 3.25 + \frac{1}{4} p_{1})

p_{1} p = 0.25 p_{1}^{2} + 3.25

解答ステップ

p_{1} (p^{1} = 3.25 + \frac{1}{4} p_{1})

= p_{1} (3.25 = p^{1} + \frac{1}{4} p_{1})

分配法則を適用する:

a (b + c) = ab + a c

a = p_{1}, b = p^{1} = 3.25, c = \frac{1}{4} p_{1}

p_{1} p^{1} = 3.25 + p_{1} \frac{1}{4} p_{1}

p_{1} p^{1} = 3.25 + \frac{1}{4} p_{1} p_{1}

簡素化

p_{1} p^{1} = 3.25 + \frac{1}{4} p_{1} p_{1} : p_{1} p = 0.25 p_{1}^{2} + 3.25

p_{1} p = 0.25 p_{1}^{2} + 3.25