2+5x-10x^2=0

Lösung

2 + 5 x - 10 x^{2} = 0

x = - \frac{- 5 + 105}{20}, x = \frac{5 + 105}{20}

Dezimale

x = - 0.26234 \dots, x = 0.76234 \dots

Schritte zur Lösung

2 + 5 x - 10 x^{2} = 0

Schreibe in der Standard Form

a x^{2} + b x + c = 0

- 10 x^{2} + 5 x + 2 = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 10 ) \cdot 2}{2 ( - 10 )}

5^{2} - 4 (- 10) \cdot 2 = 105

x_{1, 2} = \frac{- 5 \pm 105}{2 ( - 10 )}

Trenne die Lösungen

x_{1} = \frac{- 5 + 105}{2 ( - 10 )}, x_{2} = \frac{- 5 - 105}{2 ( - 10 )}

x = \frac{- 5 + 105}{2 ( - 10 )} : - \frac{- 5 + 105}{20}

x = \frac{- 5 - 105}{2 ( - 10 )} : \frac{5 + 105}{20}

Die Lösungen für die quadratische Gleichung sind:

x = - \frac{- 5 + 105}{20}, x = \frac{5 + 105}{20}

so l v e f or t, s = v t + \frac{a t ^{2}}{2}

x^{2} = (33) (63 + 33)

2 a^{2} + 5 a + 3 = 0

so l v e f or x, f = k x^{2} + (x + 1) x + k + 2

3 x^{2} + 20 x + 33 = 0