faktorisieren 1/4 x^2-25/36 y^{16}

Lösung

faktorisieren

\frac{1}{4} x^{2} - \frac{25}{36} y^{16}

(\frac{1}{2} x + \frac{5}{6} y^{8}) (\frac{1}{2} x - \frac{5}{6} y^{8})

Schritte zur Lösung

\frac{1}{4} x^{2} - \frac{25}{36} y^{16}

\frac{1}{4} x^{2} = (\frac{1}{2} x)^{2}

\frac{25}{36} y^{16} = (\frac{5}{6} y^{8})^{2}

= (\frac{1}{2} x)^{2} - (\frac{5}{6} y^{8})^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

(\frac{1}{2} x)^{2} - (\frac{5}{6} y^{8})^{2} = (\frac{1}{2} x + \frac{5}{6} y^{8}) (\frac{1}{2} x - \frac{5}{6} y^{8})

= (\frac{1}{2} x + \frac{5}{6} y^{8}) (\frac{1}{2} x - \frac{5}{6} y^{8})

s im pl i f y (2 + i)^{3}

f a c t or 3 q^{3} - 3 q

f a c t or 18 n^{5} + 16 n^{3} - 10 n^{2}

s im pl i f y 3 (- 2)^{3}

3 x - 5 \leq 10