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受欢迎的代数 >

0=40-5t-5t^2

解答

0 = 40 - 5 t - 5 t^{2}

解答

t = - \frac{1 + 33}{2}, t = \frac{33 - 1}{2}

+1

十进制

t = - 3.37228 \dots, t = 2.37228 \dots

求解步骤

0 = 40 - 5 t - 5 t^{2}

交换两边

40 - 5 t - 5 t^{2} = 0

改写成标准形式

a x^{2} + b x + c = 0

- 5 t^{2} - 5 t + 40 = 0

使用求根公式求解

t_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 5 ) \cdot 40}{2 ( - 5 )}

(- 5)^{2} - 4 (- 5) \cdot 40 = 533

t_{1, 2} = \frac{- ( - 5 ) \pm 5 33}{2 ( - 5 )}

将解分隔开

t_{1} = \frac{- ( - 5 ) + 5 33}{2 ( - 5 )}, t_{2} = \frac{- ( - 5 ) - 5 33}{2 ( - 5 )}

t = \frac{- ( - 5 ) + 5 33}{2 ( - 5 )} : - \frac{1 + 33}{2}

t = \frac{- ( - 5 ) - 5 33}{2 ( - 5 )} : \frac{33 - 1}{2}

二次方程组的解是:

t = - \frac{1 + 33}{2}, t = \frac{33 - 1}{2}

作图

流行的例子

(6 x + 4)^{2} = 16

solvefor x,9x^2+12xy+4y^2-18x-16y-11=0

so l v e f or x, 9 x^{2} + 12 x y + 4 y^{2} - 18 x - 16 y - 11 = 0

16x^2-235x+151=0

16 x^{2} - 235 x + 151 = 0

因式分解 3x^2+1=-13x-3

f a c t or 3 x^{2} + 1 = - 13 x - 3

[(7x(x))/(2+(-7))]=21

[\frac{7 x ( x )}{2 + ( - 7 )}] = 21