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受欢迎的代数 >

(b-x)/a+(ax)/b+(x+b)/2 =x+a

解答

\frac{b - x}{a} + \frac{a x}{b} + \frac{x + b}{2} = x + a

解答

x = b; 2 ba \neq = 0, b \neq = \frac{2 a ^{2}}{2 + a}

求解步骤

\frac{b - x}{a} + \frac{a x}{b} + \frac{x + b}{2} = x + a

乘以最小公倍数

2 b (b - x) + 2 a^{2} x + ba (x + b) = x \cdot 2 ba + 2 b a^{2}; 2 ba \neq = 0

乘开

2 b (b - x) : 2 b^{2} - 2 b x

2 b^{2} - 2 b x + 2 a^{2} x + ba (x + b) = x \cdot 2 ba + 2 b a^{2}

乘开

ba (x + b) : ba x + b^{2} a

2 b^{2} - 2 b x + 2 a^{2} x + ba x + b^{2} a = x \cdot 2 ba + 2 b a^{2}; 2 ba \neq = 0

将

2 b^{2}

到右边

- 2 b x + 2 a^{2} x + ba x + b^{2} a = x \cdot 2 ba + 2 b a^{2} - 2 b^{2}; 2 ba \neq = 0

将

b^{2} a

到右边

- 2 b x + 2 a^{2} x + ba x = x \cdot 2 ba + 2 b a^{2} - 2 b^{2} - b^{2} a; 2 ba \neq = 0

将

x 2 ba

para o lado esquerdo

- 2 b x + 2 a^{2} x - ba x = 2 b a^{2} - 2 b^{2} - b^{2} a; 2 ba \neq = 0

分解

- 2 b x + 2 a^{2} x - ba x : x (- 2 b + 2 a^{2} - ba)

x (- 2 b + 2 a^{2} - ba) = 2 b a^{2} - 2 b^{2} - b^{2} a; 2 ba \neq = 0

两边除以

- 2 b + 2 a^{2} - ba; 2 ba \neq = 0, b \neq = \frac{2 a ^{2}}{2 + a}

x = b; 2 ba \neq = 0, b \neq = \frac{2 a ^{2}}{2 + a}

作图

流行的例子

solvefor x,(x+k)^2=x^2-2x+k^2

so l v e f or x, (x + k)^{2} = x^{2} - 2 x + k^{2}

4-2(y-1)=3(2-y)-10

4 - 2 (y - 1) = 3 (2 - y) - 10

\frac{x}{7} = 3 x + 5

- 5 x + 4 = - 2 x + 2

log_{10}(3)(x-2)=-1

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