簡約-1/2 x^3y^2-7y^5+x^3y^2

解

簡約

- \frac{1}{2} x^{3} y^{2} - 7 y^{5} + x^{3} y^{2}

- 7 y^{5} + \frac{1}{2} x^{3} y^{2}

解答ステップ

- \frac{1}{2} x^{3} y^{2} - 7 y^{5} + x^{3} y^{2}

条件のようなグループ

= - 7 y^{5} + x^{3} y^{2} - \frac{1}{2} x^{3} y^{2}

共通項をくくり出す

x^{3} y^{2} : x^{3} y^{2} (1 - \frac{1}{2})

= - 7 y^{5} + x^{3} y^{2} (1 - \frac{1}{2})

1 - \frac{1}{2} = \frac{1}{2}

= - 7 y^{5} + x^{3} y^{2} \frac{1}{2}

= - 7 y^{5} + \frac{1}{2} x^{3} y^{2}