| 5/7 x+5|>10

Lösung

\frac{5}{7} x + 5 > 10

x < - 21 or x > 7

Intervall-Notation

(- \infty, - 21) \cup (7, \infty)

Schritte zur Lösung

\frac{5}{7} x + 5 > 10

Wende Absoluteregel an: Wenn

∣ u ∣ > a, a > 0

dann

u < - a

u > a

\frac{5}{7} x + 5 < - 10 or \frac{5}{7} x + 5 > 10

\frac{5}{7} x + 5 < - 10 or \frac{5}{7} x + 5 > 10

x < - 21 or x > 7

f a c t or 7 x^{2} + 2 x

f a c t or p^{2} + 8 p + 7

- 2 x + 3 - x = 3 x - 15

∣ x ∣ > 0

100 x^{2} = 4