7^{1-x}=49^{3x+1}

Lösung

7^{1 - x} = 4 9^{3 x + 1}

x = - \frac{1}{7}

Dezimale

x = - 0.14285 \dots

Schritte zur Lösung

7^{1 - x} = 4 9^{3 x + 1}

Wende Exponentenregel an

1 - x = 2 (3 x + 1)

Löse

1 - x = 2 (3 x + 1) : x = - \frac{1}{7}

x = - \frac{1}{7}

so l v e f or x, e^{y} = 2^{x}

2^{2 x} - 2^{x + 1} = 8

9^{x} = 3^{x} - 3

so l v e f or x, b = a \cdot (1 + \frac{63}{100})^{x}

3^{x} + x - 4 = 0