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人気のある代数 >

solvefor x,x^{2/3}+y^{2/3}=1

解

解く

x, x^{\frac{2}{3}} + y^{\frac{2}{3}} = 1

解

x = 1 - 3 y^{\frac{2}{3}} + 3 y^{\frac{4}{3}} - y^{2} {- 1 \leq y \leq 1}, x = - 1 - 3 y^{\frac{2}{3}} + 3 y^{\frac{4}{3}} - y^{2} {- 1 \leq y \leq 1}

解答ステップ

x^{\frac{2}{3}} + y^{\frac{2}{3}} = 1

y^{\frac{2}{3}}

を右側に移動します

x^{\frac{2}{3}} = 1 - y^{\frac{2}{3}}

equationの両辺を以下の累乗にする:

3 : x^{2} = 1 - 3 y^{\frac{2}{3}} + 3 y^{\frac{4}{3}} - y^{2}

x^{2} = 1 - 3 y^{\frac{2}{3}} + 3 y^{\frac{4}{3}} - y^{2}

解く

x^{2} = 1 - 3 y^{\frac{2}{3}} + 3 y^{\frac{4}{3}} - y^{2} : x = 1 - 3 y^{\frac{2}{3}} + 3 y^{\frac{4}{3}} - y^{2}, x = - 1 - 3 y^{\frac{2}{3}} + 3 y^{\frac{4}{3}} - y^{2}

x = 1 - 3 y^{\frac{2}{3}} + 3 y^{\frac{4}{3}} - y^{2}, x = - 1 - 3 y^{\frac{2}{3}} + 3 y^{\frac{4}{3}} - y^{2}

解を検算する:

x = 1 - 3 y^{\frac{2}{3}} + 3 y^{\frac{4}{3}} - y^{2} {- 1 \leq y \leq 1}, x = - 1 - 3 y^{\frac{2}{3}} + 3 y^{\frac{4}{3}} - y^{2} {- 1 \leq y \leq 1}

解答は

x = 1 - 3 y^{\frac{2}{3}} + 3 y^{\frac{4}{3}} - y^{2} {- 1 \leq y \leq 1}, x = - 1 - 3 y^{\frac{2}{3}} + 3 y^{\frac{4}{3}} - y^{2} {- 1 \leq y \leq 1}

グラフ

人気の例

solvefor x,x^{2/3}+y^{2/3}=4

so l v e f or x, x^{\frac{2}{3}} + y^{\frac{2}{3}} = 4

sqrt(4*(x+5)^2)=6

4 \cdot (x + 5)^{2} = 6

solvefor x,x^{2/3}+y^{2/3}=7

so l v e f or x, x^{\frac{2}{3}} + y^{\frac{2}{3}} = 7

a/(5-sqrt(2x+5))=3

\frac{a}{5 - 2 x + 5} = 3

solvefor x,z=x*(x^2+y^2)^{-1/2}

so l v e f or x, z = x \cdot (x^{2} + y^{2})^{- \frac{1}{2}}