0=-16t^2+32t+1584

解

0 = - 16 t^{2} + 32 t + 1584

t = - 9, t = 11

解答ステップ

0 = - 16 t^{2} + 32 t + 1584

辺を交換する

- 16 t^{2} + 32 t + 1584 = 0

解くとthe二次式

t_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 ( - 16 ) \cdot 1584}{2 ( - 16 )}

3 2^{2} - 4 (- 16) \cdot 1584 = 320

t_{1, 2} = \frac{- 32 \pm 320}{2 ( - 16 )}

解を分離する

t_{1} = \frac{- 32 + 320}{2 ( - 16 )}, t_{2} = \frac{- 32 - 320}{2 ( - 16 )}

t = \frac{- 32 + 320}{2 ( - 16 )} : - 9

t = \frac{- 32 - 320}{2 ( - 16 )} : 11

二次equationの解:

t = - 9, t = 11