因式分解 x^2+0.8x+0.16

解答

因式分解

x^{2} + 0.8 x + 0.16

(x + 0.4)^{2}

求解步骤

x^{2} + 0.8 x + 0.16

将

x^{2} + 0.8 x + 0.16

改写为

x^{2} + 2 x \cdot 0.4 + (0.16)^{2}

= x^{2} + 2 x \cdot 0.4 + (0.16)^{2}

使用完全平方公式:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = x, b = 0.4

= (x + 0.4)^{2}

f a c t or m^{2} + m^{3} - n^{2} - n^{3}

f a c t or \frac{y ( x y - 4 x )}{y - 4}

f a c t or a x - a + b x - b + c x - c

f a c t or I n (e^{4})

f a c t or \frac{4 - 2 i}{2}