因式分解 e^{10}-2e

解答

因式分解

e^{10} - 2 e

e (e^{9} - 2)

求解步骤

e^{10} - 2 e

使用指数法则:

a^{b + c} = a^{b} a^{c}

e^{10} = e^{9} e

= e^{9} e - 2 e

因式分解出通项

e

= e (e^{9} - 2)

f a c t or d^{2} + \frac{5}{4} d + 1

f a c t or - 28 b + (- 13)

f a c t or 4 a^{2} - 1 a z + 4 a^{2} - z^{2}

s im pl i f y x^{(2)} + y^{(2)} + 6 x - 4 y - 15

f a c t or - 4 x c (x - c)^{2} (2 c (x - c))