展開する v(24,-3,12,0)yv(6,-3,5,-4)

解

展開する

v (24, - 3, 12, 0) y v (6, - 3, 5, - 4)

24 vv y, 6, - 24 vv y, 3, 5, - 24 vv y, 4 - 3 vv y, 12, 0 \cdot 6, 3, 12, 0 \cdot 3, 5, 3, 12, 0 \cdot 4

解答ステップ

v (24, - 3, 12, 0) y v (6, - 3, 5, - 4)

= (24, - 3 \cdot 12 \cdot 0,,) (6, - 3 \cdot 5,, - 4) vv y

拡張

(24, - 3, 12, 0) (6, - 3, 5, - 4) : 24, 6, - 24, 3, 5, - 24, 4 - 3, 12, 0 \cdot 6, 3, 12, 0 \cdot 3, 5, 3, 12, 0 \cdot 4

= v y v (24, 6, - 24, 3, 5, - 24, 4 - 3, 12, 0 \cdot 6, 3, 12, 0 \cdot 3, 5, 3, 12, 0 \cdot 4)

拡張

v y v (24, 6, - 24, 3, 5, - 24, 4 - 3, 12, 0 \cdot 6, 3, 12, 0 \cdot 3, 5, 3, 12, 0 \cdot 4) : 24 vv y, 6, - 24 vv y, 3, 5, - 24 vv y, 4 - 3 vv y, 12, 0 \cdot 6, 3, 12, 0 \cdot 3, 5, 3, 12, 0 \cdot 4

= 24 vv y, 6, - 24 vv y, 3, 5, - 24 vv y, 4 - 3 vv y, 12, 0 \cdot 6, 3, 12, 0 \cdot 3, 5, 3, 12, 0 \cdot 4