展开 (6x+3y=1,8)(x+y=4)

解答

展开

(6 x + 3 y = 1, 8) (x + y = 4)

6 x^{2} + 6 x y = 4

求解步骤

(6 x + 3 y = 1, 8) (x + y = 4)

= (6 x + 3 \cdot 1 \cdot 8 =, y) (x + 4 = y)

使用 FOIL 方法:

(a + b) (c + d) = a c + a d + b c + b d

a = 6 x, b = 3 y = 1, 8, c = x, d = y = 4

6 xx + 6 x y = 4 + 3 y = 1, 8 x + 3 y = 1, 8 y = 4

乘开

6 xx + 6 x y : 6 x^{2} + 6 x y

6 x^{2} + 6 x y = 4

e x p an d (3 x^{2} - 14 x + 16) \circ (x - 5)

e x p an d \frac{3}{( 5 - 4 x ) ^{4}}

e x p an d (- 3 e^{t^{2}} + 5) (2)

e x p an d 4 (3 x + 10 = 16)

e x p an d \frac{5 s ^{2} + s + 25}{s ( s ^{2} + 5 )}