erweitern ((y^6-4)^2)/(16y^6)

Lösung

erweitern

\frac{( y ^{6} - 4 ) ^{2}}{16 y ^{6}}

\frac{y ^{6}}{16} - \frac{1}{2} + \frac{1}{y ^{6}}

Schritte zur Lösung

\frac{( y ^{6} - 4 ) ^{2}}{16 y ^{6}}

(y^{6} - 4)^{2} = y^{12} - 8 y^{6} + 16

= \frac{y ^{12} - 8 y ^{6} + 16}{16 y ^{6}}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{y ^{12} - 8 y ^{6} + 16}{16 y ^{6}} = \frac{y ^{12}}{16 y ^{6}} - \frac{8 y ^{6}}{16 y ^{6}} + \frac{16}{16 y ^{6}}

= \frac{y ^{12}}{16 y ^{6}} - \frac{8 y ^{6}}{16 y ^{6}} + \frac{16}{16 y ^{6}}

Streiche

\frac{y ^{12}}{16 y ^{6}} : \frac{y ^{6}}{16}

= \frac{y ^{6}}{16} - \frac{8 y ^{6}}{16 y ^{6}} + \frac{16}{16 y ^{6}}

Streiche

\frac{8 y ^{6}}{16 y ^{6}} : \frac{1}{2}

= \frac{y ^{6}}{16} - \frac{1}{2} + \frac{16}{16 y ^{6}}

Teile die Zahlen:

\frac{16}{16} = 1

= \frac{y ^{6}}{16} - \frac{1}{2} + \frac{1}{y ^{6}}

e x p an d \frac{x ^{3} ( 3 x + 8 )}{12}

e x p an d \frac{( 2 s + 1 )}{s ( s + 1 ) ^{2}}

e x p an d (2 x + 2) e^{2}

e x p an d (x + π)^{2} + (x + π)

e x p an d a (2, - 3) y b (8, - 10)