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受欢迎的代数 >

solvefor x,g(x+2)=x^2-10x-3

解答

求解

x, g (x + 2) = x^{2} - 10 x - 3

解答

x = \frac{10 + g + g ^{2} + 28 g + 112}{2}, x = \frac{10 + g - g ^{2} + 28 g + 112}{2}

求解步骤

g (x + 2) = x^{2} - 10 x - 3

展开

g (x + 2) : xg + 2 g

xg + 2 g = x^{2} - 10 x - 3

交换两边

x^{2} - 10 x - 3 = xg + 2 g

将

2 g

para o lado esquerdo

x^{2} - 10 x - 3 - 2 g = xg

将

xg

para o lado esquerdo

x^{2} - 10 x - 3 - 2 g - xg = 0

改写成标准形式

a x^{2} + b x + c = 0

x^{2} - (10 + g) x - 3 - 2 g = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 10 - g ) \pm ( - 10 - g ) ^{2} - 4 \cdot 1 \cdot ( - 3 - 2 g )}{2 \cdot 1}

化简

(- 10 - g)^{2} - 4 \cdot 1 \cdot (- 3 - 2 g) : g^{2} + 28 g + 112

x_{1, 2} = \frac{- ( - 10 - g ) \pm g ^{2} + 28 g + 112}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( - 10 - g ) + g ^{2} + 28 g + 112}{2 \cdot 1}, x_{2} = \frac{- ( - 10 - g ) - g ^{2} + 28 g + 112}{2 \cdot 1}

x = \frac{- ( - 10 - g ) + g ^{2} + 28 g + 112}{2 \cdot 1} : \frac{10 + g + g ^{2} + 28 g + 112}{2}

x = \frac{- ( - 10 - g ) - g ^{2} + 28 g + 112}{2 \cdot 1} : \frac{10 + g - g ^{2} + 28 g + 112}{2}

二次方程组的解是:

x = \frac{10 + g + g ^{2} + 28 g + 112}{2}, x = \frac{10 + g - g ^{2} + 28 g + 112}{2}

作图

流行的例子

x (2 x - 9) = 0

3 y^{2} + 7 y + 10 = 3

因式分解 2t^2+5=7t

f a c t or 2 t^{2} + 5 = 7 t

x^{2} + 6 x - 35 = 0

solvefor x,(5x+8)(12-12x)=0

so l v e f or x, (5 x + 8) (12 - 12 x) = 0