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受欢迎的代数 >

solvefor x,f(x+1)=3x^2-4x+1

解答

求解

x, f (x + 1) = 3 x^{2} - 4 x + 1

解答

x = \frac{4 + f + f ^{2} + 20 f + 4}{6}, x = \frac{4 + f - f ^{2} + 20 f + 4}{6}

求解步骤

f (x + 1) = 3 x^{2} - 4 x + 1

展开

f (x + 1) : x f + f

x f + f = 3 x^{2} - 4 x + 1

交换两边

3 x^{2} - 4 x + 1 = x f + f

将

f

para o lado esquerdo

3 x^{2} - 4 x + 1 - f = x f

将

x f

para o lado esquerdo

3 x^{2} - 4 x + 1 - f - x f = 0

改写成标准形式

a x^{2} + b x + c = 0

3 x^{2} - (4 + f) x + 1 - f = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 4 - f ) \pm ( - 4 - f ) ^{2} - 4 \cdot 3 ( 1 - f )}{2 \cdot 3}

化简

(- 4 - f)^{2} - 4 \cdot 3 (1 - f) : f^{2} + 20 f + 4

x_{1, 2} = \frac{- ( - 4 - f ) \pm f ^{2} + 20 f + 4}{2 \cdot 3}

将解分隔开

x_{1} = \frac{- ( - 4 - f ) + f ^{2} + 20 f + 4}{2 \cdot 3}, x_{2} = \frac{- ( - 4 - f ) - f ^{2} + 20 f + 4}{2 \cdot 3}

x = \frac{- ( - 4 - f ) + f ^{2} + 20 f + 4}{2 \cdot 3} : \frac{4 + f + f ^{2} + 20 f + 4}{6}

x = \frac{- ( - 4 - f ) - f ^{2} + 20 f + 4}{2 \cdot 3} : \frac{4 + f - f ^{2} + 20 f + 4}{6}

二次方程组的解是:

x = \frac{4 + f + f ^{2} + 20 f + 4}{6}, x = \frac{4 + f - f ^{2} + 20 f + 4}{6}

作图

流行的例子

(x)=0.03x^2+2x+50

(x) = 0.03 x^{2} + 2 x + 50

5 x^{2} = 4 + x

100+60L-12L^2=0

100 + 60 L - 12 L^{2} = 0

(x + 9)^{2} = 256

y^{2} = 256