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受欢迎的代数 >

(3n-2)=(n(3n-1))/2

解答

(3 n - 2) = \frac{n ( 3 n - 1 )}{2}

解答

n = \frac{4}{3}, n = 1

+1

十进制

n = 1.33333 \dots, n = 1

求解步骤

(3 n - 2) = \frac{n ( 3 n - 1 )}{2}

在两边乘以

2

2 (3 n - 2) = n (3 n - 1)

展开

2 (3 n - 2) : 6 n - 4

展开

n (3 n - 1) : 3 n^{2} - n

6 n - 4 = 3 n^{2} - n

交换两边

3 n^{2} - n = 6 n - 4

将

4

para o lado esquerdo

3 n^{2} - n + 4 = 6 n

将

6 n

para o lado esquerdo

3 n^{2} - 7 n + 4 = 0

使用求根公式求解

n_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 \cdot 4 = 1

n_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 3}

将解分隔开

n_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 3}, n_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 3}

n = \frac{- ( - 7 ) + 1}{2 \cdot 3} : \frac{4}{3}

n = \frac{- ( - 7 ) - 1}{2 \cdot 3} : 1

二次方程组的解是:

n = \frac{4}{3}, n = 1

作图

流行的例子

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