c^2+c-12=0

解

c^{2} + c - 12 = 0

c = 3, c = - 4

解答ステップ

c^{2} + c - 12 = 0

解くとthe二次式

c_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 12) = 7

c_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 1}

解を分離する

c_{1} = \frac{- 1 + 7}{2 \cdot 1}, c_{2} = \frac{- 1 - 7}{2 \cdot 1}

c = \frac{- 1 + 7}{2 \cdot 1} : 3

c = \frac{- 1 - 7}{2 \cdot 1} : - 4

二次equationの解:

c = 3, c = - 4