M=((1+i)^11)/((32(1-i)))

解答

M = \frac{( 1 + i ) ^{1} 1}{( 32 ( 1 - i ) )}

M = \frac{i}{32}

求解步骤

M = \frac{( 1 + i ) ^{1} \cdot 1}{( 32 ( 1 - i ) )}

化简

\frac{( 1 + i ) ^{1} \cdot 1}{32 ( 1 - i )} : \frac{i}{32}

M = \frac{i}{32}

a^{2} x + (a - 5) = (a + 5) x

x + (- 4) = 9

- 8 m + 14 = 2 m - 16

so l v e f or w, t = r + \frac{k}{2} w

(x - 1)^{2} + 1 = x^{2}