f=2(1)^3-3(1)^2+7

Lösung

f = 2 (1)^{3} - 3 (1)^{2} + 7

f = 6

Schritte zur Lösung

f = 2 (1)^{3} - 3 (1)^{2} + 7

Vereinfache

2 \cdot 1^{3} - 3 \cdot 1^{2} + 7 : 6

f = 6

2 x + 1 = 17

y + 8 = 20

\frac{x + 3}{4} - 2 = \frac{5 x - 2}{5}

f = 2 (4) - 3

\frac{14}{6} y + \frac{6}{2} = 2 y - 2