solvefor t,y=(1+at)(Ct)^{-2}

Lösung

löse nach

t, y = (1 + a t) (Ct)^{- 2}

t = \frac{a + a ^{2} + 4 C ^{2} y}{2 C ^{2} y}, t = \frac{a - a ^{2} + 4 C ^{2} y}{2 C ^{2} y}; C \neq = 0, C^{2} y \neq = 0

Schritte zur Lösung

y = (1 + a t) (Ct)^{- 2}

Fasse zusammen

y = \frac{1 + t a}{C ^{2} t ^{2}}

Multipliziere beide Seiten mit

t^{2}

y t^{2} = \frac{1 + t a}{C ^{2}}

Löse

y t^{2} = \frac{1 + t a}{C ^{2}} : t = \frac{a + a ^{2} + 4 C ^{2} y}{2 C ^{2} y}, t = \frac{a - a ^{2} + 4 C ^{2} y}{2 C ^{2} y}; C^{2} y \neq = 0

t = \frac{a + a ^{2} + 4 C ^{2} y}{2 C ^{2} y}, t = \frac{a - a ^{2} + 4 C ^{2} y}{2 C ^{2} y}; C \neq = 0, C^{2} y \neq = 0

so l v e f or d, \frac{ab}{d} + c = e

1 + \frac{6}{y - 2} = \frac{3 y}{y - 2}

\frac{3}{x + 2} = \frac{x}{x + 1}

\frac{x + 2}{x - 1} = 2

\frac{3}{x} = \frac{2}{6}