0.2=(9t)/(t^2+4)

解答

0.2 = \frac{9 t}{t ^{2} + 4}

t = \frac{45 + 7 41}{2}, t = \frac{45 - 7 41}{2}

十进制

t = 44.91093 \dots, t = 0.08906 \dots

求解步骤

0.2 = \frac{9 t}{t ^{2} + 4}

在两边乘以

t^{2} + 4

0.2 (t^{2} + 4) = 9 t

解

0.2 (t^{2} + 4) = 9 t : t = \frac{45 + 7 41}{2}, t = \frac{45 - 7 41}{2}

t = \frac{45 + 7 41}{2}, t = \frac{45 - 7 41}{2}

4.47 = \frac{0.01}{16 x ^{2}}

4 = \frac{3}{2 - x} + \frac{3}{2 + x}

18 = \frac{1000}{0.707 h ( 3.5 )}

so l v e f or x, \frac{- 1}{x ^{2}} = 0

- \frac{3}{x} = \frac{11}{3 x} - 5