3^x=(1/3)^{x+1}

Lösung

3^{x} = (\frac{1}{3})^{x + 1}

x = - \frac{1}{2}

Dezimale

x = - 0.5

Schritte zur Lösung

3^{x} = (\frac{1}{3})^{x + 1}

Wende Exponentenregel an

x = - (x + 1)

Löse

x = - (x + 1) : x = - \frac{1}{2}

x = - \frac{1}{2}

8 1^{x - 1} = 2 7^{x}

4^{x} - 3 \cdot 2^{x + 1} + 8 = 0

5^{3 - 2 x} = 5^{- x}

2^{5 x + 1} = 8 1^{x - 2}

5^{x^{2} - 5 x + 6} = 1