(x+8)^2(x-9)<0

Lösung

(x + 8)^{2} (x - 9) < 0

x < - 8 or - 8 < x < 9

Intervall-Notation

(- \infty, - 8) \cup (- 8, 9)

Schritte zur Lösung

(x + 8)^{2} (x - 9) < 0

Identifiziere die Intervalle

x < - 8 or - 8 < x < 9

f a c t or 2 x^{2} y^{2} + 8 x y

x^{2} + 2 x + 1 > 0

2 (x + 3) x = 5

∣ 8 x + 3 ∣ > 14

15 - \frac{1}{6} n = \frac{1}{6} n - 1